We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.More informationAgree
profileMeerathiya Shivam
asked 2020-03-13 05:23:48 
A train covers a certain distance at a uniform speed. If the train had been $6$ kilometre per hour faster, it would have taken $4$ hour less than the scheduled time and if the train was slower by $6$ kilometre per hour it would have taken $6$ hour more than the schedule time. Find length of the journey.
like 0 dislike 0 comment
answered 2020-03-18 07:23:38 

Solution 1

Refer formula

Speed $=\dfrac{6×6(4+6)}{6×6-6×4}=30\text{ km/hr}$

Required distance $=30×4\left(1+\dfrac{30}{6}\right)=720\text{ km}$

Solution 2

Let distance and speed be $x$ km and $v$ km/hr respectively. From the given statements, we can form the following equations.



solving these equation yields, $x=720$ and $v=30$

That is, required distance is $720$ km

A similar problem is provided here

like 0 dislike 0 comment

Answer This Question