We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.More informationAgree

The age of a young man and his wife sum to $52$ years. In seven years time, the man will be twice as old as his wife. Find the age of the man and his wife

Present age of the man $=37$ Present age of his wife $=52-37=15$

Solution 2

Sum of their ages after $7$ years $=52+7+7=66.$ At this time their ages are in the ratio $2:1$ and hence man's age is $66×\dfrac{2}{3}=44$ and wife's age is $66×\dfrac{1}{3}=22$

Present age of the man $=44-7=37$ Present age of his wife $=22-7=15$