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In an examination, there are three subjects A, B and C. One student has to pass in each subject$. 20\%$ students failed in A$,22\%$ students failed in B and $16\%$ failed in C. The total number of students passing the whole examination lies between 0 0 comment dev

$22\%$ students failed in B, can include $20\%$ students failed in A, and $16\%$ failed in C. Therefore, best case is $(100-22)\%=78\%$ pass.

$20\%$ students failed in A, $22\%$ students failed in B and $16\%$ failed in C can be totally distinct. Therefore, maximum failure can be $(20+22+16)\%=58\%.$ That is, $(100-58)\%=42\%$ pass.

Therefore, total number of students passing the whole examination lies between $42\%$ and $78\%$ 0 0 comment sagar shetty

Highest probability $=22\%$ fail
Lowest probability $=20\%+22\%+16\%$ fail

Therefore
Highest probability of passing$=(100-22)\%=78\%$
Lowest probability of passing$=(100-58)\%=42\%$

Hence passing students percentage lies between $42\%$ to $78\%.$ 0 0 comment

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