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profileAppu Sasi
asked 2020-03-06 19:55:04 
In an examination, there are three subjects A, B and C. One student has to pass in each subject$. 20\%$ students failed in A$,22\%$ students failed in B and $16\%$ failed in C. The total number of students passing the whole examination lies between
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profiledev
answered 2020-03-18 19:15:55 

$22\%$ students failed in B, can include $20\%$ students failed in A, and $16\%$ failed in C. Therefore, best case is $(100-22)\%=78\%$ pass.

$20\%$ students failed in A, $22\%$ students failed in B and $16\%$ failed in C can be totally distinct. Therefore, maximum failure can be $(20+22+16)\%=58\%.$ That is, $(100-58)\%=42\%$ pass.

Therefore, total number of students passing the whole examination lies between $42\%$ and $78\%$

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profilesagar shetty
answered 2020-03-15 12:51:52 

Highest probability $=22\%$ fail
Lowest probability $=20\%+22\%+16\%$ fail

Therefore
Highest probability of passing$=(100-22)\%=78\%$
Lowest probability of passing$=(100-58)\%=42\%$

Hence passing students percentage lies between $42\%$ to $78\%.$

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