×
Custom Search
cancel
×
×
Vanitha Kona
A tub contains a solution with $83\%$ water and $17\%$ spirit. $10$ liters of the solution is removed and replaced with water. The proportion of spirit is now $15\dfrac{1}{9}\%.$ How much does the tub hold?
0 0 comment
dev
$10$ litre solution contains $\left(17\%-15\dfrac{1}{9}\%\right)\%=1\dfrac{8}{9}\%=\dfrac{17}{9}\%$ spirit
Therefore $(10×9)=90$ litre solution contains $17\%$ spirit
Therefore capacity of the tub $=90$ liter