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Subtract $1$ from $24$ to obtain left side of the answer.

$24-1=23$

Subtract each digit of $23$ from $9$ to obtain right side of the answer.

$9-2=7,~9-3=6.$ That is, $76$

Hence answer is $2376$

Subtract $1$ from $2358$ to obtain left side of the answer.

$2358-1=2357$

Subtract each digit of $2357$ from $9$ to obtain right side of the answer.

$9-2=7,~9-3=6,~9-5=4,~9-7=2.$ That is, $7642$

Hence answer is $23577642$

Since the number of digits in $99999$ is $5,$ rewrite $758$ as $00758.$ Subtract $1$ from $00758$ to obtain left side of the answer.

$00758-1=00757$

Subtract each digit of $00757$ from $9$ to obtain right side of the answer.

$9-0=9,~ 9-0=9,9-7=2,~ 9-5=4,~ 9-7=2$. That is, $99242$

Hence answer is $0075799242$ or $75799242$

$897 × 99=897(100-1)=89700-897=88803$

Deepak

2014-10-16 13:32:35

Great but its trick doesn't follow $(45879×999=?)$ this type simplification

Aniket

2015-11-19 12:29:06

best way is $45879(1000-1)$

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Raj

2014-07-10 19:33:34

How to do this $12158×999$

Bz, $12158-1=12157$

$99999-12157=87842$

Here, right Answer is $12145842,$ where center value $45$ How to get in answer?

s

2015-02-11 10:12:09

When number of 9s are less than number of digit in other number The method is slightly different

here 12158*999 .It has 3 9's and other number has 5 digit

So divide the other number in to two group from right .Where right most group contain as much digit as number of 9s

that is 12158 to 2 group 12 and 158(because 3 9's)

then add 1 to the left group 12+1=13

now subtract this number from original number : 12158 - 13 = 12145

now take right most group 158 subtract it form 999+1 : 1000 - 158 = 842

So the result is combine this group 12145842

__example 2__

45612*999

45 and 612

45+1=46

45612 - 46 = 45566 => 1

1000 - 612 = 388 => 2

combine 1 and 2 => 45566388

__example 3__

4214*999

4 and 214

4214 - 5 = 4209

1000 - 214 = 786

so answer is 4209786

here 12158*999 .It has 3 9's and other number has 5 digit

So divide the other number in to two group from right .Where right most group contain as much digit as number of 9s

that is 12158 to 2 group 12 and 158(because 3 9's)

then add 1 to the left group 12+1=13

now subtract this number from original number : 12158 - 13 = 12145

now take right most group 158 subtract it form 999+1 : 1000 - 158 = 842

So the result is combine this group 12145842

45612*999

45 and 612

45+1=46

45612 - 46 = 45566 => 1

1000 - 612 = 388 => 2

combine 1 and 2 => 45566388

4214*999

4 and 214

4214 - 5 = 4209

1000 - 214 = 786

so answer is 4209786

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Anuradha

2014-07-14 20:28:46

I don't think this method can be used for problems like $12158×999$ where number of digits > number of $9\text{s}$

One method for such cases is $12158×999=12158(1000-1)=12158000-12158=12145842$

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ABDUL MUKEEM

2013-10-10 14:46:20

$758×99999$

to solve these type of question, there are $5$ nines$(9)$ so add zeros with digit as

$75800000$

i added $5$ zeros becoz of $5$ times of nine$(9)$

now subtract digit from it

$75800000-758=75799242$

this is the required ans.

sunitha naidu

2016-02-17 05:21:37

$758(100000-1)=75800000-758=75799242$

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SANJAY PAUL

2015-09-15 12:19:30

Just quick trick.

$786×99$

First take last $2$ digit: $86$

$100-86=14$

Write down at right: $14$

Then add $1$ to first digit: $1+7=8$

Then $786-8=778$

Right answer is $77814$

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