first 5250 is divisible by 5. on dividing we get 1050.
in order to show that 5250 is div. by 25, we have to show that 5250 is divisible by two 5's one by one i.e. 1050 is divisible by 5 and it is because the last digit is 0. therefore 5250 is divisible by 25.
It is very good.This pre-algebra information very interesting and important for the students. Anar
It is very very good explanation. But i did not understand the divisibility rule 11 example 4. There we need to find sum of odd numbered digits and sum of even numbered digits. Then, why there is 9+4 and 5+8. I hope u'll clear this. Thank u so much
digits in odd positions (i.e., first and third digits from left) are 9 and 4, sum = 9+4=13 digits in even positions (i.e., second and fourth digits from left) are 5 and 8, sum = 5+8=13
Actually we can count from any direction. for example, if you count from right, digits in odd positions (i.e., first and third digits from right) are 8 and 5, sum = 8+5=13 digits in even positions (i.e., second and fourth digits from right) are 4 and 9, sum = 4+9=13
This is true for all numbers. please revert for any clarification
It is very good explanation ,equation, important note and additional short note not only for student but also for teacher, really I would like to thank you
Take any combination of numbers from 2,2,2,2,3,3 and their product will be a divisor of 144
Among the numbers 2,2,2,2,3,3 , there are four identical 2s and two identical 3s
Total number of combinations possible = 5*3-1 = 14 (from the formula - Number of ways of selecting one or more than one objects out of S1 alike objects of one kind, S2 alike objects of the second kind ,S3 alike objects of the third kind and so on ... Sn alike objects of the nth kind is (S1 + 1) (S2 + 1)(S3 + 1)...(Sn + 1) - 1) Required number of divisors is 14. But we have to take 1 also as a factor. So required number of divisors will be 15