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In this section, you can find numerous aptitude questions with answers and explanation. The quantitative aptitude questions with answers mentioned above covers various categories and extremely helpful for competitive exams. All the answers are explained in detail with very detailed answer descriptions.

The quantitative aptitude questions mentioned above also contain aptitude questions asked for various placement exams and competitive exams. These will help students who are preparing for any type of competitive examinations.

Quantities aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT),MAT, GMAT, IBPS Exam, CSAT, CLAT , Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams , Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

Anusree

2015-07-13 17:12:04

4x+3y=17---->eqn.(1)

5x-2y=4------>eqn.(2)

In elimination method, we can eliminate y by multiplying eqn 1 with 2 and eqn 2 with 3,

8x+6y=34

15x-6y=12

On adding the above eqns we get as,

8x+6y=34

+

15x-6y=12

=

23x=46

x=46/23 = 2

Then on substituting the value of x in either equation 1 or 2 we get y,

Lets substitute x in eqn 2,

5*2-2*y=4

10-2y=4

6=2y

y=6/2=3.

thus x=2,y=3.

5x-2y=4------>eqn.(2)

In elimination method, we can eliminate y by multiplying eqn 1 with 2 and eqn 2 with 3,

8x+6y=34

15x-6y=12

On adding the above eqns we get as,

8x+6y=34

+

15x-6y=12

=

23x=46

x=46/23 = 2

Then on substituting the value of x in either equation 1 or 2 we get y,

Lets substitute x in eqn 2,

5*2-2*y=4

10-2y=4

6=2y

y=6/2=3.

thus x=2,y=3.

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ramya

2015-03-12 05:39:03

A dealer mixes tea costing rs.6.92 per kg with tea coasting rs.7.77 per kg and sells the mixture at 8.80 per kg and earns a profit for 17 1/2% on his sale price. In what proportion does he mix them?

Raj

2015-03-14 05:01:54

Profit = 17.5%

Selling Price of 1 kg mixture = 8.8

Profit on his sale price = 8.8 * 17.5/100 = 1.54

Cost Price of 1 Kg mixture = 7.26

By rule of alligation

Cost Price of 1 Kg tea (type1) Cost Price of 1 Kg tea (type2)

6.92 7.77

\ /

\ /

Cost Price of

1 Kg mixture

7.26

/ \

/ \

(7.77-7.26) (7.26- 6.92)

Required ratio = (7.77-7.26) : (7.26- 6.92)

= 0.51 : 0.34

= 51 : 34

= 3 : 2

Selling Price of 1 kg mixture = 8.8

Profit on his sale price = 8.8 * 17.5/100 = 1.54

Cost Price of 1 Kg mixture = 7.26

By rule of alligation

Cost Price of 1 Kg tea (type1) Cost Price of 1 Kg tea (type2)

6.92 7.77

\ /

\ /

Cost Price of

1 Kg mixture

7.26

/ \

/ \

(7.77-7.26) (7.26- 6.92)

Required ratio = (7.77-7.26) : (7.26- 6.92)

= 0.51 : 0.34

= 51 : 34

= 3 : 2

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Bharat

2015-03-29 07:02:38

6.92*x + 7.77*y = 100*8.80*(x+y)/117.50

solve for x & y we get

.54x = .28y

x:y= 14:27

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Raj

2015-04-06 20:17:37

Note that here profit of 17.5% is on sale price

"6.92*x + 7.77*y = 100*8.80*(x+y)/117.50" is true only of the profit is calculted on cost price as normal .

So here the correct eq will be 6.92*x + 7.77*y = 82.5/100 *8.80*(x+y)

6.92*x + 7.77*y = 7.26x + 7.26y

0.34x = 0.51y

x/y = 0.51/0.34 = 51/34 = 3/2

"6.92*x + 7.77*y = 100*8.80*(x+y)/117.50" is true only of the profit is calculted on cost price as normal .

So here the correct eq will be 6.92*x + 7.77*y = 82.5/100 *8.80*(x+y)

6.92*x + 7.77*y = 7.26x + 7.26y

0.34x = 0.51y

x/y = 0.51/0.34 = 51/34 = 3/2

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kiran

2015-03-10 02:32:53

By putting interest and by seeing the explanation we can understand the problems

very well.

komal

2015-03-05 17:58:53

( ) + ( )+ ( )= 30

U can use (1,3,5,7,9,11,13,15)

These no. Only

Also repet numbers.

Barkha

2015-03-20 08:35:33

(15)+(7)+(9)=30

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vishvanath

2015-03-17 12:59:45

(11-1)+(13-3)+(15-5)=30

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0

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