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Quantitative Aptitude Questions and Answers with Explanation

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In this section, you can find numerous aptitude questions with answers and explanation. The quantitative aptitude questions with answers mentioned above covers various categories and extremely helpful for competitive exams. All the answers are explained in detail with very detailed answer descriptions.

The quantitative aptitude questions mentioned above also contain aptitude questions asked for various placement exams and competitive exams. These will help students who are preparing for any type of competitive examinations.

Quantities aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT),MAT, GMAT, IBPS Exam, CSAT, CLAT , Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams , Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

Comments(188)

profileManish agarwal
2015-04-25 17:42:14 
15+13+1+1=30
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profileGeeta Rauthan
2015-04-07 15:12:26 
1+1+7+7+7+7=30
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profileEJAZ MIAN
2015-04-02 02:53:40 
Dear friends, please tell me how I will for the test of GAT which is included three subjects such as analytical reasoning questions, verbal and quantitative reasoning question. But I dont have any idea how solved these questions please help me... 

wish u good luck...

thanks a lot...
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profileraja
2015-03-30 01:06:07 
The 7th term of an AP is -15,and 16 term 30. Find the term and common difference
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profileDev
2015-04-07 18:24:10 
nth term of an AP = a + (n - 1)d  where a= the first term , d= common difference

a + 6d = -15   ------(1)
a + 15d = 30  ------(2)
(2)-(1) gives 9d = 45
d = 5

a = -15 - (6*5) = -45
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profileSubhra Dev
2015-03-21 18:49:38 
a man lost half of its initial amount in the gambling after playing 3 rounds. the rule of gambling is that if he wins he will receive rupees 100, he has to give 50% of the total amount after each round luckily he won all the 3 rounds. the initial amount with which he started the gambling was?
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profileDev
2015-04-05 17:23:05 
Let the initial amount be x

After first round, he gets Rs.100 and total amount becomes (x+100).
he has to give 50% of (x+100).  Remaining money is 50% of (x+100) = (x+100)/2 = x/2+50

After second round, he gets Rs.100 and total amount becomes x/2+50+100 = x/2+150
remaining money = 50% of (x/2+150)= x/4+75

Similarly, remaining amount after third round = 50% of (x/4+75+100) = (x/4+175)/2

remaining amount after third round = half of the initial amount
(x/4+175)/2 = x/2
x/4+175 = x
x+700=4x
3x=700

x = 700/3
initial amount = Rs.700/3
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profileabc
2015-07-10 08:45:06 
The answer is 700 because before the third time the amount of money left will be x/4 + 75 and after the 3rd round he will be left with x/4 + 175. So we will equate x/4 + 175 with x/2 .
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profileMay
2015-03-21 08:19:16 
A is twice as old as B.If in 18 years A will be 5/4 times as old as B will be then,Find B's present age.
A)6
B)12
C)24
D)30
E)54
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profileDev
2015-03-21 13:06:29 
Let age of A and B be 2x and x

In 18 years A will be 5/4 times as old as B
(2x+18) = 5/4 * (x+18)
4(2x +18) = 5(x+18)
8x + 72 = 5x + 90
3x = 18
x = 6 which is the present age of B
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