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Quantitative Aptitude Questions and Answers with Explanation

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In this section, you can find numerous aptitude questions with answers and explanation. The quantitative aptitude questions with answers mentioned above covers various categories and extremely helpful for competitive exams. All the answers are explained in detail with very detailed answer descriptions.

The quantitative aptitude questions mentioned above also contain aptitude questions asked for various placement exams and competitive exams. These will help students who are preparing for any type of competitive examinations.

Quantities aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT),MAT, GMAT, IBPS Exam, CSAT, CLAT , Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams , Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

Comments(188)

profileAnil
2015-04-07 04:58:32 
The height of a room is 5m and capacity is 500cu.m. if the room is square how much paper of two metre width is required to cover the walls?
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profileAnanya Jain
2015-05-18 06:45:20 
400 for covering 4 walls.
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profileshemurr
2015-05-01 06:31:51 
10? i guess
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profileDev
2015-04-08 20:15:13 
question is not clear. What is the length of the paper piece mentioned to cover the walls?
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profiledinesh
2015-04-02 16:55:02 
you can use these numbers 1,3,5,7,9,11,13,15

? +?+ ?+ +?+ ?=30

you can repeat the number many times
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profilevasundhara
2015-05-30 06:13:33 
13+7+9+1=30
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profilejeevitha
2015-04-20 09:41:07 
1,5,11,13
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profileTripti Garg
2015-04-17 05:47:14 
The answer is :
5+3+1+7+11+3=30
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profileDev
2015-04-08 18:13:44 
I think what he meant is expressing 30 as the sum of 5 numbers from {1,3,5,7,9,11,13,15}

Question does not say if we can use additional operators. Assuming that it is permitted.
3! + 5 + 7 + 11 + 1  is one option if so

if no additional operators are allowed, it is not possible as the sum of odd numbers is always odd when the count of the odd numbers is odd
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profileImamdeen.M
2015-04-07 15:44:05 
0+0+0+15+15
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