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Ques No.2 Let the radii of the 3 spheres be r1, r2 and r3 r1 =6, r2 = 8 and r3= 10
the radius of the new sphere formed after melting the above 3 spheres
be r. the volume of the new sphere will be the total volume of the 3
spheres with radius r1, r2 and r3
ie., 4/3 pi r cube = 4/3 pi ( r1 cube+r2 cube+r3 cube)
dividing by 4/3 pi r cube = r1 cube+r2 cube+ r3 cube = 6*6*6 + 8*8*8 + 10*10*10 = 216+512+1000 =1728
Since 12* 12*12= 1728 r = 12
Let the radii of the 3 spheres be r1, r2 and r3 r1 =6, r2 = 8 and r3= 10
New sphere Area = πr3 = π(6×6×6 + 8×8×8 +10×10×10) r3 = 216+512+1000 r3 = 1728 r = 12 diameter = 2×r = 2×12= 24 cm