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# Mixture and Alligation #8

 8. A jar full of whiskey contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is A. $\dfrac{3}{4}$ B. $\dfrac{3}{2}$ C. $\dfrac{2}{3}$ D. $\dfrac{4}{3}$

Explanation:

Concentration of alcohol in 1st Jar = 40%
Concentration of alcohol in 2nd Jar = 19%
After the mixing, Concentration of alcohol in the mixture = 26%

By rule of alligation,

 Concentration of alcohol in 1st Jar Concentration of alcohol in 2nd Jar 40% 19% Mean 26% 26-19=7 40-26=14

Hence ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2

i.e., $\dfrac{2}{1+2}=\dfrac{2}{3}$ part of the whisky is replaced.

Mohan
2016-11-25 16:34:38
1st and 2nd whiskeys are mixed in ratio 1:2
so we can take total mixture = 1+2 = 3
so
liquid 1= 1/3
liquid 2= 2/3
i.e. replaced liquid is 2/3 same as 2nd whiskey
Gkrishna
2014-10-13 08:41:01
Explanation answer has ratio 1:2 while there is no 1:2 option for this question
Ajitha Kumari
2014-10-16 22:11:30
Ratio of 1st and 2nd quantities is obtained as 1 : 2
in other words, in the mixture, Quantity of first liquid : Quantity of the second liquid  = 1 : 2

it means, the first liquid is only 1/3 in the mixture
so 2/3 of the mixture is replaced
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