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4. Two vessels A and B contain spirit and water in the ratio 5 : 2 and 7 : 6 respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in vessel C containing spirit and water in the ratio 8 : 5 ? | |

A. 7 : 9 | B. 3: 4 |

C. 9 : 7 | D. 4 : 3 |

Answer: Option A

Explanation:

Let Cost Price(CP) of 1 litre spirit be Rs.1

Quantity of spirit in 1 litre mixture from vessel A $=\dfrac{5}{7}$

Cost Price(CP) of 1 litre mixture from vessel A = Rs. $=\dfrac{5}{7}$

Quantity of spirit in 1 litre mixture from vessel B $=\dfrac{7}{13}$

Cost Price(CP) of 1 litre mixture from vessel B = Rs. $=\dfrac{7}{13}$

Quantity of spirit to be obtained in 1 litre mixture from vessel C $=\dfrac{8}{13}$

Cost Price(CP) of 1 litre mixture from vessel C(Mean Price) = Rs. $=\dfrac{8}{13}$

By rule of alligation,

CP of 1 litre mixture from vessel A | CP of 1 litre mixture from vessel B | |||||||||

$\dfrac{5}{7}$ | $\dfrac{7}{13}$ | |||||||||

Mean Price | ||||||||||

$\dfrac{8}{13}$ | ||||||||||

$\dfrac{8}{13}-\dfrac{7}{13}=\dfrac{1}{13}$ | $\dfrac{5}{7}-\dfrac{8}{13}=\dfrac{9}{91}$ |

=> Mixture from Vessel A : Mixture from Vessel B

$=\dfrac{1}{13}:\dfrac{9}{91}=7:9$

Manish Kumar

2016-08-12 16:31:53

let amount is 7x and 13y in vessels A and B respectively.

so, (5x+7y)/(2x+6y)=8/5

x/y=13/9

So ratio of amount in A/B =7x/13y =(7/13)*(13/9)=7/9

so, (5x+7y)/(2x+6y)=8/5

x/y=13/9

So ratio of amount in A/B =7x/13y =(7/13)*(13/9)=7/9

Nitin

2016-03-11 06:34:55

I fail to understand that as per rule, cheaper quantity should be in the left extreme and dearer should be in the right and d-m and m-c. 7/13 is lesser than 5/7 then how formula changed completely?

jiju

2016-03-18 09:37:35

It does not matter. You can change the order and do the calculations accordingly (as given in this answer). Both will give you same result. Try and see.

Please go through "rule of alligation" and its proof (given by*Raj under comments)* under important formulas

Please go through "rule of alligation" and its proof (given by

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Sai Arun

2015-04-03 03:40:23

how u resolved this by simply putting spirit and water ratio in vessel B 7/13 when it is 2/6 i.e 1/3 simplify properly do not adjust explain me theoritical clarification if u can

saraswathi

2014-08-27 14:02:33

Quantity of spirit in 1 litre mixture from vessel B = 7/13 how. Sir tell me immediately plz

Ani

2014-09-01 17:35:11

Vessel B contain spirit and water in the ratio 7 : 6

Quantity of spirit in Vessel B = Total Quantity * 7/(7+6) = Total Quantity * 7/13

in 1 litre mixture , it is 1 * 7/13 = 7/13

Is it clear?

Quantity of spirit in Vessel B = Total Quantity * 7/(7+6) = Total Quantity * 7/13

in 1 litre mixture , it is 1 * 7/13 = 7/13

Is it clear?

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