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2. Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety of tea in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, what is the price of the third variety per kg ? | |

A. Rs.175.50 | B. Rs.180 |

C. Rs.182.50 | D. Rs.170.5 |

Answer: Option A

Explanation:

Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed in the ratio 1 : 1

So their average price $=\dfrac{\left(126 + 135 \right)}{2} = 130.5$

Hence let's consider that the mixture is formed by mixing two varieties of tea, one at Rs. 130.50 per kg and the other at Rs. $x$ per kg in the ratio 2 : 2, i.e., 1 : 1. Now let's find out $x$.

By rule of alligation,

Cost of 1 kg of 1st kind of tea | Cost of 1 kg of 2nd kind of tea | |||||||||

130.50 | $x$ | |||||||||

Mean Price | ||||||||||

153 | ||||||||||

$(x-153)$ | 22.50 |

$(x-153):22.5=1:1\\\Rightarrow x-153=22.50\\\Rightarrow x=153+22.5=175.5$

Ashish

2015-05-21 10:48:20

Mixture is 4 kg so

126*1+135*1+2*x/4=153

261+2x=153*4

2x=351

x=175.50

126*1+135*1+2*x/4=153

261+2x=153*4

2x=351

x=175.50

mango_man

2014-02-22 18:20:42

Posted in yahoo by some user

1 : 1 :2

let x be the third mixture

126: 135 :2x = 153

:>(126 + 135 + 2x)/4 = 153

(261 + 2x ) =4*153

2x = 612 - 261

2x = 351

:. x = 175.50

:>the price of the third variety per kg: 175.50

1 : 1 :2

let x be the third mixture

126: 135 :2x = 153

:>(126 + 135 + 2x)/4 = 153

(261 + 2x ) =4*153

2x = 612 - 261

2x = 351

:. x = 175.50

:>the price of the third variety per kg: 175.50

d

2014-04-22 09:41:07

hw it came divided by 4?

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Sandhya

2014-07-10 15:51:30

the sum of the ratios 1+1+2=4...soo did divided by 4.

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