asked 2017-01-30 14:33:29
There are $4$ boys and $4$ girls. They sit in a row randomly. What is the chance that all the girls do not sit together.
Without any restrictions, number of possible arrangements $=8!$
Group the $4$ girls and consider as a single girl. then there are $5$ persons and they can be arranged in $5!$ ways. The $4$ girls can be arranged among themselves in $4!$ ways.
Therefore, number of ways in which all the $4$ girls will always sit together
Hence, number of ways in which all the $4$ girls do not sit together
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