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Question

Number of ways can $1146600$ be written as the product of two factors are

2016-10-29 05:12:26

Geetha
1 Answer

Ans: $108$

$1146600=2^3×3^2×5^2×7^2×13^1$

(from the above, it is also clear that $1146600$ is not a perfect square)

Number of factors of $1146600$

$=(3+1)(2+1)(2+1)(2+1)(1+1)=216$

i.e., there are $216$ factors for $1146600$.

Each of these factors have corresponding pair such that their product is $1146600$

Number of such different pairs $=\dfrac{216}{2}=108$

$1146600=2^3×3^2×5^2×7^2×13^1$

(from the above, it is also clear that $1146600$ is not a perfect square)

Number of factors of $1146600$

$=(3+1)(2+1)(2+1)(2+1)(1+1)=216$

i.e., there are $216$ factors for $1146600$.

Each of these factors have corresponding pair such that their product is $1146600$

Number of such different pairs $=\dfrac{216}{2}=108$