Speed Mathematics Overview
Introduction

Once you understand the chapters in these tutorials of speed mathematics, you will be able to solve complex mathematical calculations very fast and accurately. You can do these complex mathematical problems mentally.

The principles in these tutorials are taken from various systems like Indian Vedic Mathematics and the German Trachtenberg System.

Vedic Mathematics

Vedic Mathematics is the ancient system of Indian Mathematics. It is originated from "Atharva Vedas", the fourth Veda. This wonderful method is reintroduced to the world by Swami Bharati Krisna Tirtha ji Mahaharaj The book Vedic Mathematics was written by Jagadguru Swami Sri Bharati Krishna Tirthaji Maharaja. He describes Vedic Mathematics as a system of mental calculation.

In Vedic Mathematics, huge problems can be solved very easily and quickly. This is the beauty of it. Vedic Mathematics uses a very simple system. The calculation strategies provided by Vedic mathematics are very powerful and can be applied to various calculation methods in arithmetic and algebra.

The tutorials in this section makes you aware how powerful this system is. Once you learn this system, you can solve big mathematical problems mentally

Trachtenberg System of Mathematics

Jakow Trachtenberg created the Trachtenberg system of mathematics. It is system of quick mental calculation. Researches indicates that the system reduces the time for mathematical operations up to a good extent. Trachtenberg system is not only speedy, but accurate and simple.

 
 
 
Comments(28) Sign in (optional)
showing 1-10 of 28 comments,   sorted newest to the oldest
rani
2015-01-07 12:42:44 
Karthik read 7/13 th of a book in 1st week and 5/9 th of the remaining book in 2nd week. If there were 96 pages unread after 2nd week, how many pages were there in the book ?

1) 518
2) 452
3) 468
4) 502
5) 396
(2) (1) Reply
Aayush
2015-12-23 17:47:38 
It should be a multiple of 13 so, 468 among the options.
(1) (0) Reply
Nano
2015-11-14 00:02:27 
96 pages were unread
so on second week have 5/9

So unread pages = 1 - 5/9 = 4/9
96*9/4 = 216

then, on first week unread pages were 216
total pages = 216*13/6= 468

So answer is 468
(1) (0) Reply
Vijay Katkuri
2015-11-07 06:38:57 
Given 96 left..
Lets Calculate on remaining pages for 2nd week then 1st week based on given data.
its ratio is 4/9
So..4x/9=96 this gives x=216 wich is 2nd week total.
Where as first week ratio is 6x/13=216 wich gives 468.
(1) (0) Reply
pratham agrawal
2015-09-22 09:54:37 
the option which is a multiple of 9 and 13 will be the answer and i think this is the fastest method to solve this question
(0) (0) Reply
rajitha
2015-09-05 11:40:35 
let total be 1

1st week- 7/13
remaining part 1-7/13= 6/13

2nd week- 5/9(6/13)= 10/39
remaining- 6/13-10/39=8/39

as given 8/39=96 =>468
(4) (0) Reply
sai teja
2015-08-25 22:29:29 
book read = 7/13 + [(5/9)*(1-(7/13))] = 31/39 th part

book unread = 1-(31/39) = 8/39 th part

given book unread=96 so
96=8/39 th part 
total =468
(2) (0) Reply
Neha Menon
2015-07-13 18:56:06 
Ist week remaining pages 6/13 of total
2nd W.r = 4/9

Remaining pages = 96=6/13 of 4/9 of total remaining pages
Hence remaining pages = (96x13x9)/(6x4)=468
(0) (2) Reply
Abinash
2015-06-01 10:41:07 
Let the total book pages are X.
Then Unread page in first week was 6X/13
so after second week unread pages is 96
6X/13(4/9) = 96
x = 468
(0) (1) Reply
laxmi
2015-04-02 09:01:59 
let 1
1-7/13=6/13
let remaining book for second week is 1
1-5/9=4/9
then 4part =96
then 9 part=216=1 means 6/13
so 6part=216
so 13 part=36*13=468
(0) (1) Reply
123Next Go
showing 1-10 of 28 comments
 
Add a new comment...  (Use Discussion Board for posting new aptitude questions.)

Name:
Email: (optional)
0 + 0 = (please answer the simple math question)

Post Your Comment
X  
View & Edit Profile Sign out
X
Sign in
Google
Facebook
Twitter
Yahoo
LinkedIn
X