Once you understand the chapters in these tutorials of speed mathematics, you will be able to solve complex mathematical calculations very fast and accurately. You can do these complex mathematical problems mentally.

The principles in these tutorials are taken from various systems like Indian Vedic Mathematics and the German Trachtenberg System.

Vedic Mathematics is the ancient system of Indian Mathematics. It is originated from "Atharva Vedas", the fourth Veda. This wonderful method is reintroduced to the world by Swami Bharati Krisna Tirtha ji Mahaharaj The book Vedic Mathematics was written by Jagadguru Swami Sri Bharati Krishna Tirthaji Maharaja. He describes Vedic Mathematics as a system of mental calculation.

In Vedic Mathematics, huge problems can be solved very easily and quickly. This is the beauty of it. Vedic Mathematics uses a very simple system. The calculation strategies provided by Vedic mathematics are very powerful and can be applied to various calculation methods in arithmetic and algebra.

The tutorials in this section makes you aware how powerful this system is. Once you learn this system, you can solve big mathematical problems mentally

Jakow Trachtenberg created the Trachtenberg system of mathematics. It is system of quick mental calculation. Researches indicates that the system reduces the time for mathematical operations up to a good extent. Trachtenberg system is not only speedy, but accurate and simple.

1) 518

2) 452

3) 468

4) 502

5) 396

so on second week have 5/9

So unread pages = 1 - 5/9 = 4/9

96*9/4 = 216

then, on first week unread pages were 216

total pages = 216*13/6= 468

So answer is 468

Lets Calculate on remaining pages for 2nd week then 1st week based on given data.

its ratio is 4/9

So..4x/9=96 this gives x=216 wich is 2nd week total.

Where as first week ratio is 6x/13=216 wich gives 468.

1st week- 7/13

remaining part 1-7/13= 6/13

2nd week- 5/9(6/13)= 10/39

remaining- 6/13-10/39=8/39

as given 8/39=96 =>468

book unread = 1-(31/39) = 8/39 th part

given book unread=96 so

96=8/39 th partÂ

total =468

2nd W.r = 4/9

Remaining pages = 96=6/13 of 4/9 of total remaining pages

Hence remaining pages = (96x13x9)/(6x4)=468

Post Your Comment