### Important Formulas - Profit and Loss

Comments(47)

Siva
05 Jul 2014 9:55 PM

If a person sells 1000kg sugar at 8% and 18% profits in two parts and his net profit is 14%, what amount of 1000 kg he sold for 8%profit please tell the answer

Ajay
06 Jul 2014 8:31 PM

Assume cost price of 1Kg sugar is Rs.1

Then total cost price of 1000 Kg sugar = Rs.1000

Net profit is 14% . So his total selling price = 1000 * 114/100 = Rs.1140

Let x kg he sells at 8% profit and (1000-x) at 18% profit.

his total selling price = x * 108/100 + (1000-x)*118/100

x * 108/100 + (1000-x)*118/100 = 1140

108x + 118000 - 118x = 114000

4000 = 10x

x = 400

So he sells 400 kg for 8% profit.

Then total cost price of 1000 Kg sugar = Rs.1000

Net profit is 14% . So his total selling price = 1000 * 114/100 = Rs.1140

Let x kg he sells at 8% profit and (1000-x) at 18% profit.

his total selling price = x * 108/100 + (1000-x)*118/100

x * 108/100 + (1000-x)*118/100 = 1140

108x + 118000 - 118x = 114000

4000 = 10x

x = 400

So he sells 400 kg for 8% profit.

Ranga
03 Jul 2014 5:39 PM

I would like to understand more about the same.

which is the best way to learn faster.

shayan
30 Jun 2014 3:54 PM

How much percent must be added to the cost price of goods so that a profit of 20% must be made after throwing off discount of 10% from the labelled price?

plzzz answer it.

Aashir
01 Jul 2014 10:27 PM

Assume cost price is Rs. 100. To get a profit of 20%, selling price should be Rs. 120

Now take that 90% of the labelled price = 120

or labelled price = 120 *

So, required percentage is 33.33%

Now take that 90% of the labelled price = 120

or labelled price = 120 *

^{100}/_{90}= 133.33So, required percentage is 33.33%

shreoshree chakrabarty
16 May 2014 1:51 PM

60% of goods are sold at 5% loss, while the rest are sold at 10% profit.

if there is a total profit of Rs.100, then the worth of goods sold is-

(a)Rs. 5000 (b)Rs. 6000 (c)Rs. 10000 (d)Rs. 15000

please solve this question for me.....plzzz do also explain it...

Roy
18 May 2014 12:12 AM

Let total number of goods be n

and cost price per good = x

then, total cost price = nx ---(1)

Amount of loss by selling 60% of goods = (60n/100)*x*(5/100)

Amount of profit by selling remaining 40% = (40n/100)*x*(10/100)

Net profit = (40n/100)*x*(10/100) - (60n/100)*x*(5/100) which is given as 100

=> 100nx/10000) = 100

=> nx/100 = 100

=> nx= 10000

i.e., total cost price is Rs.10000

and cost price per good = x

then, total cost price = nx ---(1)

Amount of loss by selling 60% of goods = (60n/100)*x*(5/100)

Amount of profit by selling remaining 40% = (40n/100)*x*(10/100)

Net profit = (40n/100)*x*(10/100) - (60n/100)*x*(5/100) which is given as 100

=> 100nx/10000) = 100

=> nx/100 = 100

=> nx= 10000

i.e., total cost price is Rs.10000

shreoshree chakrabarty
19 May 2014 11:03 AM

thank you for giving your answer so soon....

Shreoshree Chakrabarty
18 May 2014 2:21 PM

thanxxxx a lot for your help.......

Prashant sharma
29 Apr 2014 2:17 PM

guys my math is very poor....................plz suggest me how to study so that my concept and base will become strong ....................plzzzzzzzzzzzz

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