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Important Formulas - Profit and Loss


Comments(47)


Siva 05 Jul 2014 12:25 PM
If a person sells 1000kg sugar at 8% and 18% profits in two parts and his net profit is 14%, what amount of 1000 kg he sold for 8%profit please tell the answer
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Ajay 06 Jul 2014 11:01 AM
Assume cost price of 1Kg sugar is Rs.1

Then total cost price of 1000 Kg sugar = Rs.1000

Net profit is 14% . So his total selling price = 1000 * 114/100 = Rs.1140

Let x kg he sells at 8% profit and (1000-x) at 18% profit.
his total selling price = x * 108/100 + (1000-x)*118/100

x * 108/100 + (1000-x)*118/100 = 1140
108x + 118000 - 118x = 114000
4000  = 10x
x = 400

So he sells 400 kg for 8% profit.
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Ranga 03 Jul 2014 8:09 AM
I would like to understand more about the same.

which is the best way to learn faster.
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shayan 30 Jun 2014 6:24 AM
How much percent must be added to the cost price of goods so that a profit of 20% must be made after throwing off discount of 10% from the labelled price?

plzzz answer it.
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Aashir 01 Jul 2014 12:57 PM
Assume cost price is Rs. 100.  To get a profit of 20%, selling price should be Rs. 120

Now take that 90% of the labelled price = 120
or labelled price  = 120 * 100/90 = 133.33

So, required percentage is 33.33%
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shreoshree chakrabarty 16 May 2014 4:21 AM
60% of goods are sold at 5% loss, while the rest are sold at 10% profit.
if there is a total profit of Rs.100, then the worth of goods sold is-
(a)Rs. 5000     (b)Rs. 6000        (c)Rs. 10000       (d)Rs. 15000



please solve this question for me.....plzzz do also explain it...
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Roy 17 May 2014 2:42 PM
Let total number of goods be n
and cost price per good = x

then, total cost price = nx   ---(1)

Amount of loss by selling 60% of goods =  (60n/100)*x*(5/100)
Amount of profit by selling remaining 40% =  (40n/100)*x*(10/100)

Net profit = (40n/100)*x*(10/100) - (60n/100)*x*(5/100) which is given as 100
=> 100nx/10000) = 100
=> nx/100 = 100
=> nx= 10000

i.e., total cost price is Rs.10000
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shreoshree chakrabarty 19 May 2014 1:33 AM
thank you for giving your answer so soon....
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Shreoshree Chakrabarty 18 May 2014 4:51 AM
thanxxxx  a lot for your help.......




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Prashant sharma 29 Apr 2014 4:47 AM
guys  my math is very poor....................plz suggest me how to study so that my concept and base will become  strong ....................plzzzzzzzzzzzz
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