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2) If three metallic spheres of radii 6 cms, 8 cms and 10 cms are melted to from a single sphere, the diameter of the new sphere will be:

3) Sixty men can build a wall in 40 days, but though they begin the work together, 5 men quit every ten days. The time needed to build the wall is:

4) Shyam is travelling on his cycle and has calculated to reach point 'A' at 2 PM If he travels at 10 kmph. he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach point 'A' at 1 PM:

5) An aeroplane travelling at 700 km. p. h. in level flight drops a bomb from a height of 1000 metres on a target. The time taken from releasing the bomb to hitting the target is nearest to the figure:

6) In a History examination, the average for the entire class was 80 marks. If 10% of the students scored 95 marks and 20% scored 90 marks. What was the average marks of the remaining students of the class

10*95=950

20*90=1800

950+1800+70×=80*100

×=75

d=(t-2)*15

t= 6 hrs

d= 60

60 = 5*s

speed = 12km/hr

60*10+55*10+50*10+45*10=2100 man days

300/40= 7.5 days

total days = 10+10+10+10+7.5 = 47.5 days

r*r*r=1728

r=12 cm

12*12(4/3*12*1/2+H)= 3312

4/3*12*1/2+H= 23

8+H=23

H=23-8 = 15 m

s = ut + 0.5at

^{2}

here s=1000

u=0(initial speed)

a=g=9.8 m/s

^{2}

So time can be calulated as 14.14sec

__Answer for Q2:__

If three metallic spheres melted down and formed a new sphere, volume of all three sphere will be equivalent to the volume of new sphere and final equation will be

(r1^3)+(r2^3)+(r3^3) = R^3

here,

(6^3)+(8^3)+(10^3) = R^3

=>216+512+1000 = R^3

=> R = (1728)^1/3

i.e. R = 12 cm.

Hence, diameter of the new sphere will be (2R) i.e 24cm.

S1*t1=s2*t2. (Speed 1=10 kmh, s2 is 15)

10*(14-t)=15*(12-t). (2 o'clock on 24 hrs clock is 14, while 12 is 12)

140-10t=180-15t. (t is the start time)

5t=40

t=8 hrs, means he had started journey at 8AM

D=s1*(14-t)

D=10*(14-8)

D=60 km

Time to reach destination=13-8=5 hrs

Speed=d\t=60/5=12kmh

x = d/10 ......Eqn 1.

Now,(x - 2) = d/15 or 15x - 30 = d or 15x = 30 + d or x = (d + 30)/15......Eqn 2.

From eqns 1 and 2,we have (d + 30)/15 = d/10 or 10d + 300 = 15d or 5d = 300 or d = 60 km.

Now,

x -1 = d/10 - 1 or x - 1 = 60/10 - 1 = 5 [We are talking about 1 p.m and we have chosen the time duration of upto to p.m to be x,so upto 1 p.m,it is (x -1) hours]

So,the time taken upto 1 p.m is 5 hours.Therefore,the speed = distance/time = 60/5 km/hr

= 12 km/hr

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