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In this section, you can find numerous aptitude questions with answers and explanation. The quantitative aptitude questions with answers mentioned above covers various categories and extremely helpful for competitive exams. All the answers are explained in detail with very detailed answer descriptions.

The quantitative aptitude questions mentioned above also contain aptitude questions asked for various placement exams and competitive exams. These will help students who are preparing for any type of competitive examinations.

Quantities aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT),MAT, GMAT, IBPS Exam, CSAT, CLAT , Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams , Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

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showing 1-10 of 187 comments,   sorted newest to the oldest
2015-04-09 13:59:29 
1) A water tank is hemispherical below and cylindrical at the top. If the radius is 12m and capacity is 3312*pi cubic metre the height of the cylindrical portion in metres is:

2) If three metallic spheres of radii 6 cms, 8 cms and 10 cms are melted to from a single sphere, the diameter of the new sphere will be:

3) Sixty men can build a wall in 40 days, but though they begin the work together, 5 men quit every ten days. The time needed to build the wall is:

4) Shyam is travelling on his cycle and has calculated to reach point 'A' at 2 PM If he travels at 10 kmph. he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach point 'A' at 1 PM:

5) An aeroplane travelling at 700 km. p. h. in level flight drops a bomb from a height of 1000 metres on a target. The time taken from releasing the bomb to hitting the target is nearest to the figure:

6) In a History examination, the average for the entire class was 80 marks. If 10% of the students scored 95 marks and 20% scored 90 marks. What was the average marks of the remaining students of the class
(0) (0) Reply
2016-03-16 13:38:39 
6) Suppose students = 100
(0) (0) Reply
2016-03-16 13:33:18 
4) d= t*10
t= 6 hrs
d= 60
60 = 5*s
speed = 12km/hr
(0) (0) Reply
2016-03-16 13:27:12 
3)Total man days = 2400
60*10+55*10+50*10+45*10=2100 man days
300/40= 7.5 days
total days = 10+10+10+10+7.5 = 47.5 days
(0) (0) Reply
2016-03-16 13:16:24 
02) 4/3*22/7*r*r*r =4/3*22/7*(216+512+1000)
r=12 cm
(0) (0) Reply
2016-03-16 13:10:15 
01) VOLUME , V = 22/7*12*12(4/3*12*1/2+H)= 3312*22/7
12*12(4/3*12*1/2+H)= 3312
4/3*12*1/2+H= 23
H=23-8 = 15 m
(0) (0) Reply
Ritesh Singh
2016-02-04 05:02:52 
we will have to take up physics formulae for 5th one
s = ut + 0.5at2

here s=1000
u=0(initial speed)
a=g=9.8 m/s2

So time can be calulated as 14.14sec
(0) (0) Reply
Ashutosh R
2015-08-11 12:47:55 
Answer for Q2:
If three metallic spheres melted down and formed a new sphere, volume of all three sphere will be equivalent to the volume of new sphere and final equation will be
(r1^3)+(r2^3)+(r3^3) = R^3

(6^3)+(8^3)+(10^3) = R^3
=>216+512+1000 = R^3
=> R = (1728)^1/3
i.e. R = 12 cm.

Hence, diameter of the new sphere will be (2R) i.e 24cm.
(0) (0) Reply
2015-07-31 05:52:28 
4.   Since distance is same,
S1*t1=s2*t2.            (Speed 1=10 kmh, s2 is 15)
10*(14-t)=15*(12-t).  (2 o'clock on 24 hrs clock is 14, while 12 is 12)
140-10t=180-15t.      (t is the start time)
t=8 hrs, means he had started journey at 8AM

D=60 km
Time to reach destination=13-8=5 hrs
(0) (0) Reply
2015-07-28 21:30:00 
4. Since we do not know at what time Shyam actually sets on his journey,we will consider any one of the time limits provided (either 12 p.m or 2 p.m) to be taking x hours from the time he started,that is we have consider either duration to be x (or y or z or whatever you wish to take) hours.Now, if we consider this for 2 p.m,then by time = distance/speed,we have

x = d/10 ......Eqn 1.

Now,(x - 2) = d/15 or 15x - 30 = d or 15x = 30 + d or x = (d + 30)/15......Eqn 2.

From eqns 1 and 2,we have (d + 30)/15 = d/10 or 10d + 300 = 15d or 5d = 300 or d = 60 km.

x -1 = d/10 - 1 or x - 1 = 60/10 - 1 = 5 [We are talking about 1 p.m and we have chosen the time duration of upto to p.m to be x,so upto 1 p.m,it is (x -1) hours]

So,the time taken upto 1 p.m is 5 hours.Therefore,the speed = distance/time = 60/5 km/hr
= 12 km/hr
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