12. If a square and a rhombus stand on the same base, then what is the ratio of the areas of the square and the rhombus? | |

A. equal to ½ | B. equal to ¾ |

C. greater than 1 | D. equal to 1 |

| Discuss |

Answer: Option C

Explanation:

Hence greater than 1 is the more suitable choice from the given list

Note : Proof

Consider a square and rhombus standing on the same base 'a'.
All the sides of a square are of equal length. Similarly all the sides of a rhombus are also of equal length. Since both the square and rhombus stands on the same base 'a',

Length of each side of the square = a

Length of each side of the rhombus = a

Area of the square = a^{2} ...(1)

From the diagram, sin θ = @@\dfrac{\text{h}}{a}@@

=> h = a sin θ

Area of the rhombus = ah = a × a sin θ = a^{2} sin θ ...(2)

From (1) and (2)

@@\dfrac{\text{Area of the square}}{\text{Area of the rhombus}}@@

@@=\dfrac{\text{a}^2}{\text{a}^2 \sin θ} = \dfrac{1}{\sin \text{θ}}@@

Since 0° < θ < 90°, 0 < sin θ < 1. Therefore, area of the square is greater than that of rhombus, provided both stands on same base.

*(Note that, when each angle of the rhombus is 90°, rhombus is also a square (can be considered as special case) and in that case, areas will be equal.*

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